Feature Post

Monday, October 31, 2011

Time Machine

It is not accidental configuration section using a laser to show turbulent Chaotic Micro-Flow has been used in connection with time travel. The plant has some interesting behaviors that can be seen easily. Examine the configuration means that some of the following:
Rise of critical radius r0, the YV distance, a rotation of the laser beam YU-> Z-> W-> B

For a total scattering angle DFE, the rotational movement of the laser beam results in an angular frequency / speed equal to ω = 2 * π / T. This in turn leads to a linear velocity v = ω * r, to the point of the laser beam, which is done remotely YV (as vectors of UT, ZA, WX and British Columbia).

Since V is a linear function of r, it follows that the R0 and thus a specific YV, where the linear velocity should be equal to c = 3 * 108m / s. This is, of course, during the same at r0. Assuming a relatively low T, as the speed of 10000 rpm, which is the fastest speed of the motor car, we have T = 3 / 500

Solving the equation c = v = ω * r to r, we obtain R0 ~ 286478.8m. Since r0/YV = tan (DFE / 2), we obtain: YV = r0/tan (DFE / 2), for R0 ~ 286478.8m and DFE / 2 = π / 9 gives: ~ YV 787094.3m

What does all this: If we were to set this little thing with a laser mirror angle θ = π equal to * 2.9 For example, while at a distance of 787 km ~ YV, where the radius of the scan will be approximately 286 , 5 km ~ r0, we find a 2D singular space-time [1] (check one) [2]. To create a singularity in 3D, it is necessary to generalize the three dimensions, can be done at least two ways:


A mechanical time machine based on the above principle can be realized as a mechanism of rotation, with two rotating rings (green), anchored in AB and CD:
Gyro Time Machine
To create a singularity at E, the linear velocity must be at least equal to c. As the linear velocity EH is the sum of its components EC and EC, we have: EF = EG + c. Since both mechanical rings are (almost) the same diameter, we have r * sqrt (ω12 ω22 +) = c, from which we obtain the basic equation of the time machine with n = 2 ring [4 ]:

The basic equation for the free time machine two rings

For a speed of 10000 rpm for two rings, we obtain r ~ 202.5 km.


A time machine optics based on the principle above can be done again as a gyro mechanism, but this time instead of mechanical rings, we can turn the laser beam. How many laser beams? To find out, we remember that each point on the surface of a sphere can be described by its Euler angles (α, β, γ). In addition, if a point A is rotated to a position E of Euler angles (α, β, γ), it can be shown that there are angles (a, b, c) such that the following list of operations of rotation of the point again that E [5]:

First rotation by angle a around the z axis

2. Turn the angle b around the new x-axis.

3. C angle of rotation around the z axis of the press.

Note that there are only two axes involved in the whole cycle using the angles (a, b, c). Therefore, we only need two rotating laser beams. Please note that this is the same as one of the laser beam and the two mirrors! Low reasonable inspection shows that we can use the following installation, as shown below [6]:

Time Machine with a laser gyroscope and two mirrors


Choose a coordinate system in a grid format. It is shown, then the inclination angle θ and φ the azimuth. θ be realized in the CD tray runs C and φ is built around the fourth bar B (green ellipses).

For this configuration, then, if the rotational speeds of the two mirrors, JH and GF have periods T1 and T2, then the equations for the two angles versus time t is:

1. θ (t) = ω1 * s = 2 * π * t/T1

Second φ (t) = ω2 t = 2 * π * T/T2

To create a 3D singularity, then the tip of the laser beam must have a linear velocity v satisfies the fundamental equation (above). And then the phasor describing the motion of the laser beam in 3-space as a function of time t is given by:
Phasor optical time machine

When this laser configuration is spinning fast enough, you get the (spherical) 3D radius r0 of the critical singularity. Passing some of the values, if the speed is 10000 rpm and 30000rpm, then T1 = 60 / 10000, and T2 = 60 / 30000, which is obtained r0 ~ 90.6 km.

Time Dilation

Time for an observer inside the setup is relativistically expanded and is given as:

t '= t * γ = t / sqrt (1 - (v / c) 2)

where γ is the Lorentz factor now. Note that v = r * sqrt (ω12 ω22 +), where r is the distance from the observer B, and therefore the Lorentz factor becomes:
Lorentz factor of the optical machine T1 and T2 time

Follow the chart maple relativistic time dilation in the setup:
Relativistic time dilation machine time to end, with 0 ≤ ≤ 10000/60 f1, f2 = f1 * 3 and 0 ≤ r ≤ 100 km

For example, at a distance of 90 km with a speed of 10000rpm and 30000rpm, the Lorentz factor γ ~ 8.75. This means that the observer is inside the machine, at this distance from the center, moving with a speed 8.75 times faster than the time when an outside observer. This means that the observer moves toward the future

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